## College Algebra 7th Edition

A geometric sequence has a common ratio $r$. The common ratio is multiplied to the current term to get the next term of the sequence. The common ratio is equal to the the quotient of a term and the term before it. Solve for the ratio of each pair of consecutive terms to obtain: $\dfrac{48}{3} = 16 \\\dfrac{93}{48}=\dfrac{31}{16} \\\dfrac{138}{93} = \dfrac{46}{31}$ Since the ratio is common to all pairs f consecutive terms, then the sequence is geometric. The ratios are different so the given sequence is not geometric.