#### Answer

$\$403,500$

#### Work Step by Step

We know the salary forms an arithmetic sequences with:
$a_1=30000$
And:
$d=2300$
We find the sum after 10 years:
$S_{n}= \frac{n}{2}[2a_1+(n-1)d]=403500$
$S_{10}= \frac{10}{2}[2(30000)+(10-1)(2300)]=403500$

Published by
Brooks Cole

ISBN 10:
1305115546

ISBN 13:
978-1-30511-554-5

$\$403,500$

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