College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 8, Sequences and Series - Chapter 8 Review - Concept Check - Page 639: 7

Answer

a) $\sum_{k=1}^5 k^3$ b) $2(3^2)+2(4^2)+2(5^2)$

Work Step by Step

a) First we notice the form of the general term of our sum: $k^3$. Then we notice that the sum starts with $k=1$ and ends with $k=5$. Therefore the sum can be written: $$1^3+2^3+3^3+4^3+5^3=\sum_{k=1}^5 k^3.$$ b) We rewrite the sum giving $k$ the values from $3$ to $5$: $$\sum_{k=3}^5 2k^2=2(3^2)+2(4^2)+2(5^2).$$
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