Answer
$F(0,p)$, $y=-p$.
$F(0,3)$, $y=-3$.
Work Step by Step
The graph of $x^2=4py$ is a parabola with focus $F(0,p)$ and directrix $y=-p$.
Hence the graph of $x^2=12y$ is a parabola with focus $F(0,3)$ and directrix $y=-3$.
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