College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 7, Conic Sections - Chapter 7 Test - Page 586: 4


The equation for the parabola using the information given is: $y^{2} = 16x$

Work Step by Step

The focus of this parabola is given as $(4, 0)$, so we can see that this parabola has a horizontal axis. We also know that this is a parabola that is not shifted because its vertex is at the origin, so we know that the equation for this parabola with a horizontal axis can be given as: $y^{2} = 4px$ From the information given, we can see that the value for $p$ is $4$. We can then substitute $4$ for $p$: $y^{2} = 4(4)x$ We simplify to get the equation for this particular parabola: $y^{2} = 16x$
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