Answer
$(a). (A+B)^{2}=A^{2}+AB+BA+B^{2}$
$(b).$ No it is not proper ,$AB$$\ne$$BA$.
Work Step by Step
$(a). (A+B)^{2}=(A+B)(A+B)=A^{2}+AB+BA+B^{2}$
$(b). (A+B)^{2}$$\ne$$A^{2}+2AB+B^{2}$
$AB$$\ne$$BA$ ,hence $(AB+BA)$$\ne$$2AB$
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter 6, Matrices and Determinants - Section 6.2 - The Algebra of Matrices - 6.2 Exercises - Page 512: 52
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