## College Algebra 7th Edition

a. $x=2,\quad y=1\quad z=3.$ b. $x=2-z,\ y=1-z,\ z=$ any real number. c. $x=$none, $y=$none, $z=$ none.
a. Each row of the matrix represents an equation. $x=2,\quad y=1\quad z=3.$ b. Each row of the matrix represents an equation. The last row represents 0=0, so there will be solutions. z does not have a corresponding leading 1, so we take it as a parameter (z= any real number), we back-substitute to find x and y. $x+z=2\quad\Rightarrow\quad x=2-z$ $y+z=1\quad\Rightarrow\quad y=1-z$ Answer: $x=2-z,\ y=1-z,\ z=$ any real number. c. Each row of the matrix represents an equation. The last row represents 0=$3$, an equation that no triplet x,y,z will satisfy, so there will be no solutions. Answer: $x=$none, $y=$none, $z=$ none.