College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 6, Matrices and Determinants - Chapter 6 Review - Exercises - Page 539: 38

Answer

$BAB^{-1}=\left[\begin{array}{c c} -3/2& -4&19/4\\ -1/2& -1&-11/4\\ 7& 16&13/2\end{array} \right]$

Work Step by Step

Using a graphing calculator (see attached picture), we get: $BAB^{-1}=\left[\begin{array}{c c} -3/2& -4&19/4\\ -1/2& -1&-11/4\\ 7& 16&13/2\end{array} \right]$
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