College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 5, Systems of Equations and Inequalities - Section 5.2 - Systems of Linear Equations in Several Variables - 5.3 Exercises - Page 456: 45

Answer

$x=50$ $y=60$ $z=30$

Work Step by Step

Let $x$ denote Midnight Mango Let $y$ denote Tropical Torrent Let $z$ denote Pineapple Power $\begin{cases} 8x+6y+2z=820\\ 3x+5y+8z=690\\ 3x+3y+4z=450 \end{cases}$ Multiplying Equation 2 by -8/3 and adding it to Equation 1, results in new Equation 1 $\begin{cases} 8x+6y+2z=820\\ -8x-\frac{40}{3}y-\frac{64}{3}=-1840\\ -- -- - -- -- --\\ -\frac{22}{3}y-\frac{58}{3}z=-1020 \end{cases}$ Multiplying both sides by 3, $-22y-58z=-3060$. Multiplying Equation 3 by -1 and adding it to Equation 2, results in new Equation 2. $\begin{cases} 3x+5y+8z=690\\ -3x-3y-4z=-450\\ -- -- -- -- --\\ 2y+4z=240 \end{cases}$ Multiplying the new equation 2 by 11 and adding it to the new equation 1. $\begin{cases} -22y-58z=-3060\\ 22y+44z=2640\\ -- -- -- -- --\\ -14z=-420 \end{cases}$ Thus, $z=30$. Substituting it back in, $y=60$ and $x=50$
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