Answer
$x^2+y^2\geq8$.
Work Step by Step
According to the given graph and the equation, our inequality is:
$x^2+y^2\geq8$.
This includes the shaded area and the function itself (because we have an equals sign). Notice that we used a greater-than sign to shade the graph outside the circle.
We confirm the inequality by plugging in $(0,0)$, which gives us:
$0^2+0^2\ge8$
This is a false statement, as expected because the origin is not in the shaded region. Thus, the inequality works.
