#### Answer

(a) $m(0)=13$
(b) $m(45)=6.62$ kg

#### Work Step by Step

We are given:
$m(t)=13e^{-0.015t}$
(a) We plug in $t=0$:
$m(0)=13e^{-0.015*0}=13*1=13$
(b) We plug in $t=45$:
$m(45)=13e^{-0.015*45}=13e^{-0.675}=6.62$ kg

Published by
Brooks Cole

ISBN 10:
1305115546

ISBN 13:
978-1-30511-554-5

(a) $m(0)=13$
(b) $m(45)=6.62$ kg

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