College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 4, Exponential and Logarithmic Functions - Section 4.1 - Exponential Functions - 4.1 Exercises - Page 374: 62

Answer

$\approx67,121.04$

Work Step by Step

In $A(t)=P(1+\frac{r}{n})^{nt}$ for compound interest, $P,r,n,t$ respectively stand for the principal, interest rate per year, the number of times the interest is compounded per year and the number of years. $A(t)=100000$ is the amount after $t$ years. So if we invest $P$ at an interest rate of $r=0.08$ compounded monthly ($n=12$), the amount after $t=5$ years is: $100000=P(1+\frac{0.08}{12})^{12(5)}\\P=\frac{100000}{(1+\frac{0.08}{12})^{12(5)}}\approx67121.04$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.