Answer
a) $2628.17$
b) $2694.7$
c) $2904.57$
Work Step by Step
In $A(t)=P(1+\frac{r}{n})^{nt}$ for compound interest $P,r,n,t$ respectively stand for the principal, interest rate per year, the number of times the interest is compounded per year and the number of years. $A(t)$ is the amount after $t$ years. So if we invest $P=2500$ at an interest rate of $r=0.025$ compounded daily ($n=365$), the amount after $t$ years is:
a) $A(2)=2500(1+\frac{0.025}{365})^{365(2)}\approx2628.17$
b) $A(3)=2500(1+\frac{0.025}{365})^{365(3)}\approx2694.7$
c) $A(6)=10000(1+\frac{0.03}{2})^{6(15)}\approx2904.57$
