College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 4, Exponential and Logarithmic Functions - Section 4.1 - Exponential Functions - 4.1 Exercises: 7

Answer

$f(1/2)=2$; $f(\sqrt5) \approx. 22.195$; $f(-2)\approx 0.063$; $f(0.3) \approx. 1.516$

Work Step by Step

Evaluate the function for the given values of $x$ by substituting each $x$ into $f(x)$ then using a calculator to find the exact value. When x=$\frac{1}{2}$: $f(x) = 4^x \\f(1/2)=4^{\frac{1}{2}} \\f(1/2)=2$ When $x=\sqrt5$: $f(x) = 4^x \\f(\sqrt{5}) = 4^{\sqrt5} = \\f(\sqrt5) \approx. 22.195$ When $x=-2$: $f(x)=4^x \\f(-2)=4^{-2} \\f(-2)\approx 0.063$ When $x=0.3$: $f(x)=4^x \\f(0.3) = 4^{0.3} \\f(0.3) \approx. 1.516$
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