## College Algebra 7th Edition

(a) $2x=\log_{6}25$ or: $x=\frac{1}{2}\log_{6}25$ (b) $A=e^{3}$
(a) We are given: $6^{2x}=25$ This means: $2x=\log_{6}25$ or: $x=\frac{1}{2}\log_{6}25$ (b) $\ln A=3$ We use $e$ to cancel $\ln$: $e^{\ln A}=e^{3}$ $A=e^{3}$