Answer
$2x^{3}-3x^{2}-2x=(2x-3)(x^{2}-1)-3$
Work Step by Step
$\left[\begin{array}{l}
\\
2x-3\ )\\
\\
\\
\\
\\
\\
\\
\end{array}\right. \left.\begin{array}{rrrrrrr}
x^{2} & & -1 & & \\
\hline 2x^{3} & -3x^{2} & -2x & & \\
2x^{3} & -3x^{2} & & & \\
-- & -- & & & \\
& 0 & -2x & & \\
& & -2x & +3 & \\
& & -- & -- & \\
& & & -3 &
\end{array}\right]$
$Q(x)=x^{2}-1,\quad R(x)=-3$
In the form $P(x)=D(x)\cdot Q(x)+R(x),$
$2x^{3}-3x^{2}-2x=(2x-3)(x^{2}-1)-3$
