## College Algebra 7th Edition

The $x$-intercepts of the function's graph can be found by equating each factor to zero then solving each equation to obtain: \begin{align*} -2x&=0 &\text{or}& &(x-2)^2=0\\ x&=0 &\text{or}& &x-2=0\\ x&=0 &\text{or}& &x=2\\ \end{align*} Thus, the $x$-intercepts are $0$ and $2$. The $y$_intercept of the function can be found by setting $x=0$ then solving for $y$: \begin{align*} P(0)&=-2(0)(0-2)^2\\ P(0)&=0\\ \end{align*} Thus, the $y$-intercept is $0$ Create a table of values to obtain the one below. Then, plot each ordered pair and connect the points using a smooth curve. Refer to the graph above.