## College Algebra 7th Edition

upward; $2, -6$; $-6$; minimum
RECALL: The quadratic function $f(x) = a(x-h)^2+k$ has the following properties: vertex at $(h, k)$ opens upward when $a \gt 0$ and $f(h)=k$ is its minimum value. The given quadratic function has: $h=2, k=-6$ $a=3$ Thus, the function has: its vertex at $(2, -6)$; opens upward; $f(2)=-6$ is the minimum value of $f$ Therefore, the missing expressions in the given statement (in order) are: upward; $2, -6$; $-6$; minimum