## College Algebra 7th Edition

$f^{-1}(x) = \frac{\sqrt[3] x - 5}{3}$
f(x) = $(3x + 5)^{3}$ y = $(3x + 5)^{3}$ Solve for x $\sqrt[3] y = 3x + 5$ $\sqrt[3] y - 5 = 3x$ $\frac{\sqrt[3] y - 5}{3} = x$ Interchange x with y $\frac{\sqrt[3] x - 5}{3} = y$ $\frac{\sqrt[3] x - 5}{3} = f^{-1}(x)$