## College Algebra 7th Edition

$f(x)=\frac{5}{9}x-\frac{1}{3}$
To find the equation of the line, we first find the slope between the points $(-3,\ -2)$ and $(6,\ 3)$: $m=\displaystyle \frac{-2-3}{-3-6}=\frac{-5}{-9}=\frac{5}{9}$ Next, we plug in one of the points $(6,3)$ and the slope into the point-slope formula for a line: $y-3=\displaystyle \frac{5}{9}(x-6)$ $y=\frac{5}{9}x-\frac{5*6}{9}+3$ $y=\frac{5}{9}x-\frac{10}{3}+3$ $y=\frac{5}{9}x-\frac{1}{3}$