#### Answer

Interval: $(-\infty,\ -6)\cup\ (12,\ \infty)$

#### Work Step by Step

$|x-3|>9$
We split the absolute value into the positive and negative:
$x-3>9$
$x>12$

Published by
Brooks Cole

ISBN 10:
1305115546

ISBN 13:
978-1-30511-554-5

Interval: $(-\infty,\ -6)\cup\ (12,\ \infty)$

$|x-3|>9$
We split the absolute value into the positive and negative:
$x-3>9$
$x>12$

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