College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 1, Equations and Graphs - Section 1.10 - Modeling Variation - 1.10 Exercises: 28

Answer

$H=81l^{2}w^{2}$

Work Step by Step

Since $H$ is jointly/directly proportional to the squares of $l$ and $w$, we have: $H=kl^{2}w^{2}$ We are given: $H=36$ and $l=2$ and $w= \frac{1}{3}$, so we have: $36=k(2)^{2}( \frac{1}{3})^{2}=k*4*\frac{1}{9}$ $36=\frac{4}{9}k$ $k=36*9/4=81$ So the equation is: $H=81l^{2}w^{2}$
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