## College Algebra 7th Edition

a) $x=\frac{108-y}{4}$ b) $m=\frac{8k^2}{n}$
a) $4x+y=108$ $4x=108-y$ a b) $8=\frac{mn}{k^{2}}$ $8k^{2}=mn$ $m=\frac{8k^2}{n}$