College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Are you Ready for College Algebra? - B. Diagnostic Test: Algebraic Expressions - Page XVIII: 4


a) $\frac{\sqrt 21}{7}$ b) $9+3\sqrt5$

Work Step by Step

a) $\frac{\sqrt 3}{\sqrt 7}$ = $\frac{\sqrt 3}{\sqrt 7} \times \frac{\sqrt 7}{\sqrt 7}$ = $\frac{\sqrt 3\times\sqrt 7}{\sqrt 7\times\sqrt 7}$ = $\frac{\sqrt 21}{7}$ b) $\frac{12}{3-\sqrt 5}$ = $\frac{12}{3-\sqrt 5}$ $\times$ $\frac{3+\sqrt5}{3+\sqrt 5}$ = $\frac{36+12\sqrt5}{9-5}$ = $\frac{36+12\sqrt5}{4}$ = $9+3\sqrt5$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.