College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Summary, Review, and Test - Test - Page 92: 32

Answer

a) $ 42.95 $%, underestimate, by $0.05$% b) $R=1∶ \frac{53+0.28n}{47-0.28n}$ c) $ 3$ women, accurately predicts projections shown by the graph.

Work Step by Step

a) $M=-0.28n + 47$ $n = 2003 - 1989 = 14$, as the formula works for n years after 1989. $M = -0.28(14) +47 = 42.95$% Bar Graph result = 43% Formula estimation = 42.95% Therefore, the formula is an underestimation by $0.05$% b) $R = Man:Woman$ $= 47 - 0.28n : 53+0.28n$ $= 1: \frac{53+0.28n}{47-0.28n}$ c) $n = 2014-1989=25$, 25 years after 1989 Using earlier defined formula, $1 : \frac{0.28(25)+53}{47-0.28(25)}$ $= 1:1.5$, 1.5 women per 1 man for 2 men, $1\times2 : 1.5 \times2$ $2:3$, so 3 women per 2 men Projections shown by graph = 40 men to 60 women, $40:60$ which simplifies to $1:1.5$ which is the same as our formula based result $1:1.5$ therefore $R$ accurately predicts projections shown by the Graph.
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