College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Summary, Review, and Test - Test - Page 92: 30

Answer

$27^{-\frac{5}{3}}$ = $\frac{1}{243}$

Work Step by Step

$27^{-\frac{5}{3}}$ = $\frac{1}{27^{\frac{5}{3}}}$ = $\frac{1}{\sqrt[3] {27^{5}}}$ As we know 27 = $3^{3}$ = $\frac{1}{3^{3\times\frac{5}{3}}}$ = $\frac{1}{3^{5}}$ = $\frac{1}{243}$
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