College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Summary, Review, and Test - Review Exercises - Page 90: 48


$16\sqrt 2$

Work Step by Step

$2\sqrt 50+3\sqrt 8=2\sqrt (25\times2)+3\sqrt (4\times2)=(2\times \sqrt 25\times\sqrt2)+(3\times \sqrt 4\times\sqrt2)=(2\times5\times\sqrt 2)+(3\times2\times\sqrt2)=10\sqrt2+6\sqrt2=(10+6)\sqrt 2=16\sqrt 2$ We know that $\sqrt 25=5$, because $5^{2}=25$. We know that $\sqrt 4=2$, because $2^{2}=4$.
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