College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Summary, Review, and Test - Review Exercises - Page 90: 31

Answer

$\frac{y^8}{4x^{10}}$

Work Step by Step

Use the rule of exponents to divide the exponents by subtracting them, and divide the regular numbers to simplify. Then put negative exponents back in the denominator. $\frac{7x^5y^6}{28x^{15}y^{-2}}$ $\frac{7}{28}*x^{5-15}y^{7-(-2)}$ $\frac{1}{4}x^{-10}y^8$ $\frac{y^8}{4x^{10}}$
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