Answer
Evaluating $x^{2}-5(x-y)$ for $x=6$ and $y=2$ gives $16$
Work Step by Step
Evaluate $x^{2}−5(x−y)$ if x=6 and y=2.
Let's substitute the value of x and y in the given expression.
if x=6 and y=2
$x^{2}−5(x−y)$
=$6^{2}−5(6−2)$
Apply the PEMDAS rule to evaluate all operations.
Do the operation inside the parentheses.
=$6^{2}−5(6−2)$
=$6^{2}−5(4)$
Evaluate the expression with exponent, then multiply 5 and 4.
=$6^{2}−5(4)$
=$(6· 6) - 20$
Perform the operation inside the parentheses, then subtract from left to right.
=$(6· 6) - 20$
=$36 - 20$
=$16$
therefore, $x^{2}−5(x−y)$ if x=6 and y=2 give 16.
