College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Summary, Review, and Test - Review Exercises - Page 89: 2


Evaluating $x^{2}-5(x-y)$ for $x=6$ and $y=2$ gives $16$

Work Step by Step

$x^{2}-5(x-y)$ for $x=6$ and $y=2$ Substitute $x$ by $6$ and $y$ by $2$ in the given expression: $(6)^{2}-5(6-2)=...$ Evaluate all operations and simplify: $...=36-5(4)=36-20=16$
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