College Algebra (6th Edition)

Evaluating $3+6(x-2)^{3}$ for $x=4$ gives $51$
$3+6(x-2)^{3}$ for $x=4$ Substitute $x$ by $4$ in the given expression: $3+6(4-2)^{3}=...$ Evaluate all operations and simplify: $...=3+6(2)^{3}=3+6(8)=...$ $...=3+48=51$