College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Mid-Chapter Check Point - Page 63: 28

Answer

$-x^3$

Work Step by Step

The variable $x$ will become $-x$ when the absolute value bars are removed, so when multiplied with $x^2$ the whole expression will be negative. $x^2|x|$ if $x\lt0$ $-x^3$
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