Answer
$\frac{6y^3}{x^7}$
Work Step by Step
Simplify by multiplying the terms and using the rules of exponents to add the exponents together. Then make sure to put terms with negative exponents in the denominator.
$(\frac{1}{3}x^{-5}y^4)(18x^{-2}y^{-1})$
$6x^{-5+(-2)}y^{4+(-1)}$
$6x^{-7}y^3$
$\frac{6y^3}{x^7}$
