## College Algebra (6th Edition)

$\frac{6y^3}{x^7}$
Simplify by multiplying the terms and using the rules of exponents to add the exponents together. Then make sure to put terms with negative exponents in the denominator. $(\frac{1}{3}x^{-5}y^4)(18x^{-2}y^{-1})$ $6x^{-5+(-2)}y^{4+(-1)}$ $6x^{-7}y^3$ $\frac{6y^3}{x^7}$