Answer
False.
$(x^{3}-64)= (x-4)(x^{2}+4x+16)$
Work Step by Step
Difference of two cubes,
$A^{3}- B^{3} = (A-B)(A^{2}+AB+B^{2})$
$x^{3}- 64 = x^{3}- 4^{3} $
$= (x-4)(x^{2}+4x+4^{2})$
$= (x-4)(x^{2}+4x+16)$
College Algebra (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-32178-228-3
ISBN 13:
978-0-32178-228-1
Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.5 - Page 76: 137
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
