# Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.5 - Page 76: 132

Makes sense.

#### Work Step by Step

$4x^{2}-100 = (2x+10)(2x-10)$ The first step in factoring the polynomial $4x^{2}-100$ is determining the square roots of each term because it is a binomial. The square of 4x^{2} is 2x, allowing the start of the equation look like this: $(2x ±? )(2x± ? )$. Next, we take a look at the term $-100$. The square root of 100 is 10, allowing the equation to look like this: $(2x±10)(2x±10)$ There is no middle term, meaning sum the squares of 100, must equal zero. Therefore the equation would look like this: $(2x+10)(2x-10)$, making the original statement correct.

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