## College Algebra (6th Edition)

To confirm adequate rationalization of the exercise, we solve in the following manner: $$\frac{7\sqrt {2}}{\sqrt{6}}$$ = $\frac{7\sqrt {2}}{\sqrt{6}} \times \frac{\sqrt 6}{\sqrt 6}$ = $\frac{7\sqrt {2\times6}}{\sqrt{6^2}}$ =$\frac{7\sqrt {12}}{6}$ =$\frac{7\sqrt {2^2 \times 3}}{6}$ = $\frac{7\times2\sqrt {3}}{6}$ =$\frac{7\sqrt {3}}{3}$