College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.3 - Page 50: 122

Answer

$3\sqrt 3$

Work Step by Step

$\sqrt 3 + \sqrt 12$ Split $\sqrt 12$ into two factors such that one is a perfect square. $= \sqrt 3 + \sqrt (4 \times 3)$ $= \sqrt 3 + \sqrt 4 \times \sqrt 3$ $= \sqrt 3 + 2\sqrt 3$ Apply Distributive property $= (1 + 2) \sqrt 3$ $= 3\sqrt 3$
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