## College Algebra (6th Edition)

Published by Pearson

# Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.2: 148

#### Answer

a.) 8 b.) 8 c.) You can conclude that the two different notations are interchangeable.

#### Work Step by Step

$\sqrt {16}$$\times$$\sqrt 4$ = 4$\times$2=8 $\sqrt {16\times4}$=$\sqrt {64}$=8

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