College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.2 - Page 35: 132

Answer

False; only two expressions are equivalent

Work Step by Step

Simplify all the given expressions. $(6x^6)^2=6^2\times x^{6\times2}=36x^{12}$ $(6x^3)(6x^9)=(6\times6)(x^3\times x^9)=36x^{3+9}=36x^{12}$ $36(x^3)^9=36x^{3\times9}=36x^{27}$ $6^2(x^2)^6=36x^{2\times6}=36x^{12}$ All the expressions but one are equivalent. Since $(36(x^3)^9)$ is different, the statement is false.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.