Answer
Probability of getting an odd number the first time and a number less than 3 the second time = $\frac{1}{6}$
Work Step by Step
Probability = $\frac{Favorable outcomes}{Total outcomes}$
For finding probability to get an odd number the first time when die is rolled twice
Total outcomes = 6
Favorable outcomes = (1, 3, 5) = 3
Probability of getting an odd number = $\frac{3}{6}$ = $\frac{1}{2}$
For finding probability to get a number less than 3 second time when die is rolled twice
Total outcomes = 6
Favorable outcomes = (1, 2) = 2
Probability of getting less than 3 = $\frac{2}{6}$ = $\frac{1}{3}$
Probability of getting an odd number the first time and a number less than 3 the second time = $\frac{1}{2}$$\times$$\frac{1}{3}$ = $\frac{1}{6}$
