College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 8 - Sequences, Induction, and Probability - Exercise Set 8.7 - Page 785: 47

Answer

$\frac{1}{36}$

Work Step by Step

We know that $probability=\frac{\text{number of favourable outcomes}}{\text{number of all outcomes}}$ We need to find the probability of the first roll and the probability of the second roll. Then we multiply the two probabilities to obtain the answer. For the first roll, we have $1$ good outcome out of the total of $6$. For the second roll, we also have $1$ good outcome out of the total of $6$. Hence probability$=\frac{1}{6}\cdot\frac{1}{6}=\frac{1}{36}$
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