Answer
$x^8+4x^6y+6x^4y^2+4x^2y^3+y^4$
Work Step by Step
Use the binomial theorem formula (detailed on page 754) to solve the problem. Be careful in writing each term correctly.
$(x^2+y)^4$
$1*(x^2)^4+4*(x^2)^3*(y)+6*(x^2)^2*(y)^2+4*(x^2)*(y)^3+(y)^4$
$x^8+4x^6y+6x^4y^2+4x^2y^3+y^4$