Answer
$x^3+9x^2y+27xy^2+27y^3$
Work Step by Step
Use the binomial theorem formula (detailed on page 754) to solve the problem. Be careful in writing each term correctly.
$(x+3y)^3$
$1*(x)^3+3*(x)^2*(3y)+3*(x)*(3y)^2+1*(3y)^3$
$x^3+9x^2y+27xy^2+27y^3$
