College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 8 - Sequences, Induction, and Probability - Exercise Set 8.3 - Page 741: 82

Answer

a). Total Scholarship fund at the end of 10 year = 956,792.65 b). Interest = 356,792.65

Work Step by Step

a). Invest per three month = 15000 Compound interest rate quarterly is 9% = 0.09 Total Scholarship fund at the end of n year = $\frac{P [(1 + \frac{r}{n})^{n\times t} - 1]}{\frac{r}{n}}$ Total Scholarship fund at the end of 10 year = $\frac{15000 [(1 + \frac{0.09}{4})^{4\times 10} - 1]}{\frac{0.09}{4}}$ = 15000$\times$ 63.79 = 956792.65 b). Interest =956792.65 - (15000$\times$4$\times$10) = 956792.65 - 600000 = 356792.65
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.