College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 8 - Sequences, Induction, and Probability - Exercise Set 8.3 - Page 741: 78

Answer

a). Amount received after 5 year A = 14163.2 b). Interest = 1663.2

Work Step by Step

a). Saving on first year = 2500 Compound interest rate is 6.25% = 0.0625 Amount received after n year A = $\frac{P [(1 + \frac{r}{n})^{n\times t} - 1]}{\frac{r}{n}}$ Amount received after 5 year A = $\frac{2500 [(1 + \frac{0.0625}{1})^{1\times 5} - 1]}{\frac{0.0625}{1}}$ = $\frac{2500 [(1 + 0.0625)^{5} - 1]}{0.0625}$ = $\frac{2500 [(0.4356]}{0.0625}$ = 2500 $\times$ 5.665= 14163.2 b). Interest = 14163.2 - (2500$\times$5) = 14163.2 - 12500 = 1663.2
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