College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 8 - Sequences, Induction, and Probability - Exercise Set 8.1 - Page 717: 104

Answer

Sequence: $1,5,9,13,17,...$ $a_{2}-a_{1}=4$ $a_{3}-a_{2}=4$ $a_{4}-a_{3}=4$ $a_{5}-a_{4}=4$ In the sequence each term is $4$ more than the term preceding it.

Work Step by Step

$a_{n}=4n-3$ $a_{1}=4(1)-3 = 4 -3 = 1$ $a_{2}=4(2)-3 = 8 -3 = 5$ $a_{3}=4(3)-3 = 12 -3 = 9$ $a_{4}=4(4)-3 = 16 -3 = 13$ $a_{5}=4(5)-3 = 20 -3 = 17$ Sequence: $1,5,9,13,17,...$ $a_{2}-a_{1}=5-1=4$ $a_{3}-a_{2}=9-5=4$ $a_{4}-a_{3}=13-9=4$ $a_{5}-a_{4}=17-13=4$ In the sequence each term is $4$ more than the term preceding it. This sequence is an example of Arithmetic sequence.
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