## College Algebra (6th Edition)

False, e.g. $\sum_{i=1}^{2} (-1)^i2^i=((-1)^12^1)+((-1)^22^2)=-2+4=2$ but $\sum_{i=1}^{2} (-1)^i\sum_{i=1}^{2}2^i=((-1)^1+(-1)^2)(2^1+2^2)=(-1+1)(2+4)=0\cdot6=0$ and $2\ne0$