Answer
False.
Work Step by Step
False, e.g. $\sum_{i=1}^{2} (-1)^i2^i=((-1)^12^1)+((-1)^22^2)=-2+4=2$ but $\sum_{i=1}^{2} (-1)^i\sum_{i=1}^{2}2^i=((-1)^1+(-1)^2)(2^1+2^2)=(-1+1)(2+4)=0\cdot6=0$ and $2\ne0$
College Algebra (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-32178-228-3
ISBN 13:
978-0-32178-228-1
Chapter 8 - Sequences, Induction, and Probability - Exercise Set 8.1 - Page 717: 100
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