College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 8 - Sequences, Induction, and Probability - Exercise Set 8.1 - Page 716: 96

Answer

Statement is wrong.

Work Step by Step

$(-1)^{2n}$=1 always. Hence the term will not alternate the sign.
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