College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 8 - Sequences, Induction, and Probability - Exercise Set 8.1 - Page 716: 78



Work Step by Step

See p.709: If $n$ is a positive integer, the notation $n!$ (read $n$ factorial'') is the product of all positive integers from $n$ down through 1. $n!=n(n-1)(n-2)\cdots(3)(2)(1)$ Note: $0!$ (zero factorial), by definition, is 1. $0!=1$ ------------------ $(n+1)!$ os obtained by multiplying $n!$ with $(n+1).$ So, write $\displaystyle \frac{900!}{899!}=\frac{900\cdot 899!}{899!}$ ...and reduce the fraction... $=900$
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