College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 8 - Sequences, Induction, and Probability - Concept and Vocabulary Check - Page 714: 7

Answer

(n + 3)

Work Step by Step

$\frac{(n+3)!}{(n+2)!}$ = $\frac{(n+3)(n+2)(n+1)(n)(n-1)(n-2)(n-3)- - - - -}{(n+2)(n+1)(n)(n-1)(n-2)(n-3)- - - - -}$ = (n+3)
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