Answer
(n + 3)
Work Step by Step
$\frac{(n+3)!}{(n+2)!}$
= $\frac{(n+3)(n+2)(n+1)(n)(n-1)(n-2)(n-3)- - - - -}{(n+2)(n+1)(n)(n-1)(n-2)(n-3)- - - - -}$
= (n+3)
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