Answer
The second term of the sequence [ $a_{n}$= $\frac{(-1)^{n}}{4^{n}-1}$ ]
= $\frac{1}{15}$
Work Step by Step
The second term of the sequence [ $a_{n}$= $\frac{(-1)^{n}}{4^{n}-1}$ ]
$a_{2}$= $\frac{(-1)^{2}}{4^{2}-1}$
= $\frac{1}{15}$
College Algebra (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-32178-228-3
ISBN 13:
978-0-32178-228-1
Chapter 8 - Sequences, Induction, and Probability - Concept and Vocabulary Check - Page 714: 4
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